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Finals.


Question Posted Saturday January 22 2005, 3:16 pm

I know we really aren't supposed to ask homework questions but I really need help. I have Algebra finals next week and I do NOT understand how to do these types of problems: Factor- 2x - x + 4, x - 81, and 4x - 13x - 30 = 0. Whenever I ask my algebra teacher all he says is: "HOW CAN YOU NOT GET IT????" and then he just explains it the same way all over again and I still don't get it. I'm already at a C- in his class and I'm normally an A - B and nothing lower student so this is bad. I really need help. If I don't pass this exam I could fail. Any help would be greatly appreciated.

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Additional info, added Saturday January 22 2005, 6:39 pm:
Alright, I'm sorry I didn't clarify this in my question but I'm not supposed to combine like terms. I know how to do that. I'm supposed to factor everything so that I end up with an answer that should look like this: (x-4)(x+3) or something like that. Sorry for the confusion..

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S_C answered Saturday February 5 2005, 11:30 am:
Dude, I know you asked this question like 2 weeks ago, and you probably are waaay done with factoring, but here are some math sites that deal with factoring, and other stuff
[Link](Mouse over link to see full location) and [Link](Mouse over link to see full location)

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azngemini answered Saturday January 22 2005, 5:56 pm:
ohh this is good, cuz I'm learning this in school toooo.. ya, so I'll help you with the last problem
4x - 13x - 30 = 0.
first you have to combine the like terms, in this case X, by adding it. so 4x +(- 13x), which is basically 4x - 13x, is -9x.
now the equation is
-9x-30=0
so since one side of the equation has a 0, you need to add something onto that side because you need to find the value of x.
What you do to one side, you have to do to the other. so if one of the sides had negative(-)9x, you need to add 9x to both sides. if it was a positive(+)9x, you need to subtract 9x from both sides.
so let's try it with -9x
-9x-30+9x=0+9x
is
-30=9x
now you need to find the value of x, so you have to divide 9 from both sides
-3 1/3=x

I hope you get it now, and you can ask me for more help on algebra questions if you want. sorry if it's too long

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Kr4z3y_Ch3lly answered Saturday January 22 2005, 5:10 pm:
Ok for the 1st two you cant really do them cuz they dont give you an answer! You need an answer to figure out what x is...But the very last one i cant help you with...

The last one: 4x-13x-30=0
(combine the two factors that are alike which would be 4x-13x=9x)

9x-30=0
(now add 30 to it self and 0..Always add the number that has the "x" or unidentified numer on its side. If it was a possitive 30 you would subtract 30 from each side! It would look like this...9x-30=0
+30+30)

9x=30
(since the 30 and the 30 cancle each other out..You are left with the above equation.Now you divde the 9x with it self and to the 30. Because you have to do the same to each side each time. So now it would look like this.....9x=30
-- --
9 9)

30
-- = 27 3/9= 27 1/3
9

(You divide 30 into 9 and see what yoou get since this problem doesnt come out equally you turn it into a proper fraction which is what i did ^^^^ up there. Your answer would be 27 1/3)

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Moop answered Saturday January 22 2005, 3:50 pm:
Factoring is simple. The problem with most people and factoring is that there are a billion ways to do it and many don't understand those that others look upon as simple. Assuming you're in high school, there should be many many algebra teachers (and even higher math teachers). Go to as many as you can before finals and ask them about factoring. You'll get a billion different ways to do it. I didn't learn the first time I was taught but the second worked. The method I use now makes factoring very very fast which is how I need to factor. Find one method that suits you and if you'd like the method I use I might be able to make a word document about it given proper time.

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sPicYx0hoTt answered Saturday January 22 2005, 3:21 pm:
Instant message me im in honor's math..SFTBALL SWTiE130..im excellent in math!

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KimRose answered Saturday January 22 2005, 3:20 pm:
yeah... i don't really understand the question but if you leave me a question in my site... I can talk to you through IM and help you out because I did really good in algebra 1 and 2
~KiKi

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