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Geometry problem!
Ok here is an example of a problem:
Polly Gawn is building a triangular pool. She wants the pool to be acute, with no obtuse angles. One side of the pool is 20 feet long and the other side is 48 feet long. how long does the third side have to be to make sure that pool has all acute angles?
Helppp! Please!
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I don't mean to sound rude but I don't think this site is here to do your homework for you. However, yes the people answering are correct.
CuxMiBeckNow7, actually showed you the steps.
These steps were called the pythagorean theorem. You can solve problems such as this in the futre by using it:
leg one squared + leg two squared = leg three squared.
Then after you square the two legs and add them you have to square root it and that gives you leg three(the hypotenuse or the slanted leg).
If you have the hypotenuse and another lef of the triangle and you have to find the length of a straight side you subtract in the equation, not add.
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i dont know what the answer is, but i am totaly sure that it is not 52. 52 would make it a right triangle, which means a right angle, which means they are not all acute. what you would want, is something shorter than 52. how much shorter? not really sure. there is more than one right answer though. 48 would be a good one, that gives you an isocelese triangle, and since the bottom side is shorter, all angles should be acute.
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You have to use the:
c^2=a^2+b^2 equation
acute triangle= all angle are acute and less than 90 degrees
A=20
B=48
C=C
so...
A^2= 400
B^2= 2304
C^2= C^2
400+2304=C^2
2704=C^2
take the square root of both sides
C=52
The third side has to be less than 52 feet long to make sure that the pool has all acute angles, since if it had 52, it would make it a right triangle.. having less than a 90 degree angle would make the triangle acute
Hope I helped!
--Jack
4.8.15.16.23.42
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i'm NOT 100% positive, but i think that the third side would have to be 52 feet.
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