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Algebra Question
Ok I don't really get this so could someone please explain to me how to do it thanks...
Rewrite the equation in slop-intercept form.
y-3=-2(x+1)
Thanks!
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distribute the -2
y-3=-2x-2
then add the 3
y=-2x+1
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slope-intercept form is y=mx+b where m is the slope and b is the y intercept. to change this problem into slope-intercept form:
distribute the -2 to the x and the +1
then you have y-3=-2x-2
add three to both sides to get y by itself.
y=-2x+1
:)
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Okay, slope intercept formula is y=mx+b
M is the slope
B is the intercept (line crossing the y axis)
Do it just like regular algebra. And use the PEMDAS thing to help you along (Parenthasis, Exponents, Multiplication, Division, Addition, Subtraction)
y-3= -2(x+1) ---> Start with 2(x+1)
y-3= -2x-2
Now, add 3 to both sides so that it cancels out the -3 that is next to Y
y= -2x-2+3 or y=-2x+1
Do you get it yet?
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well you have to distribute the -2 through the problem
y-3=-2x-2
then add three
y=-2x+1
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That is point-slope form. In that, you have the slope and a point but not the y-intercept. In slope-intercept form, you have the slope and the y-intercept. All you have to do is solve that problem for y. When you do, you get--
y=-2x+1
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WHAT'S SLOP INTERCEPT??
Is this slop intercept
-2x+1=3-y?
You cannot combine the x and the y because they are not {like terms}!
You can rewrite the problem
Leters to the left, numbers to the right.
I'm doing this in my math class so if you have anymore questions, ask away. If you still don't understand, drop one in my inbox!
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Slope intercept form is y = mx + b
m = the slope
b = the intercept, or where the line crosses the y-axis.
y-3 = -2(x+1) <--distribute the -2 inside the parentheses
y-3 = -2x-2 <--add 3 to both sides
y = -2x+1 <--final answer
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