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point slop form


Question Posted Friday January 7 2005, 3:27 am

how can/ can you know the y-intercept when the equation is in slope intercept form? y2-y1=m(x2-x1)
thanks.


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S_C answered Friday January 7 2005, 3:36 pm:
Just my type of question...I'm VERY good at math.
Do you mean y-y1=m(x-x1)You are not allowed to do anything with the y and x (the regular, not the one with 1 attached) Here's an example.
Say the point is 4,2 and the slope is 3
Y-2=3(X-4). You distribute the 3... 3(x) & #(-4)
so it's Y-2=3X-12 then you add 2 to both sides, so the new problem is Y=3X-10. That is Slope form... Y=MX=B And M is the slope which in my problem would be 3, or 3/1. And y intercept would be -10. Pretty much just solve fir Y instead of solving for the whole A1-B2=C thing. Or another way you can get it WITH using a1=b2=c
Same problem to make it easy...
Y-2=3(X-4) You distribute... Y-2=3x-12. Add two to both sides... Y=3x-10. Subtract 3x from both sides... -3x+y= -10, this is COVER UP METHOD. You cover up the X, pretend it IS NOT there. You get Y=-10. That is the Y intercept. Or... if you wanted to find X intercept (just like Y-int, but when it intercepts the x-axis instead of the Y) You would cover up the Y, pretend it wasn't there, and it'd say -3x=-10. Divide both sides by -3, the 1st side cancels out, and -10/-3 = 3&1/3. Hope this isn't too confusing. And I hope I'm answering your question, I wasn't totally sure what you were asking.

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Karen answered Friday January 7 2005, 3:13 pm:
We just learned this in algebra a few months ago. You have to change that equation into y=mx+b form. Just plug in the points and then simplify the equation! Just go to [Link](Mouse over link to see full location) to learn more! Hope I helped :)
-Karen

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xokristabelle answered Friday January 7 2005, 9:56 am:
You have to get it into y=mx+b form. M is the slope, x is the x-intercept, and b is the y-intercept.

For more help, go to hotmath.com.

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Moop answered Friday January 7 2005, 9:14 am:
if you have two points, plug them into the equation. Say your first point is (2,-3) and your second is (3,-1). Your equation would be (-1)-(-3)=m(3)-(2). Then you would get 2=m(1) so m (slope) = 2. Then you plug 2 into the m slot in y=mx+b (slope-intercept form) and end up with y=2x+b. From here you'd choose one of your above points and plug it in again (-3=2(2)+b). Then you simply solve for b as the y-intercept.

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toosweet4u172 answered Friday January 7 2005, 8:33 am:
Well, first you need two points or it's not a problem. Second do the problem, if you know how... then, re-arrange it to fit y=mx+b and then once you get it in that form, b = the y intercept.

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