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wow yeah im failing math


Question Posted Tuesday March 8 2005, 8:37 pm

y sqaured + 4y = 6y?
PLEASE tell me if that's right (i doubt it is), and if its not what is it and why?


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lazy_one answered Wednesday March 9 2005, 5:38 pm:
if you need help with math go to www.algebrahelp.com
or you could go to Google and look up math help.

hope i helped.

~~chelsey~~

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Erinn_the_bamf answered Wednesday March 9 2005, 3:35 pm:
No, it is not right. Squaring a number is multipling it by itself. You can look at it these ways:

4y is like saying 4 times y. So you do y times y. Then 4 times y. Then add the products together. The sum does not add up to 6 times y.

For the method above try inserting parenthesis (sp?). That would make it look like this (y*y) + (4*y).

OR

Look at it as there are for sets of y. Or for the y squared part it is y sets of y. So add y sets of y and 4 sets of y together. This does not equal 6 sets of y.

I hope I hepled! ♥ good luck

ask me any more math questions I understand this part of math very well!

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VeLvtxRevoLvr213 answered Wednesday March 9 2005, 2:43 pm:
no thats not right... y squared+ 4y = 6y is your problem. Bring the 4y over as a negative to the 6y side. That will give you y squared = 2y... get it? Well, im not sure if you do because this problem doesnt have a very clear solution. You could make things called 'restictions' but thats a long thing to explain and i dont feel like it. Drop one into my inbox for math help! i've been in advanced classes my whole life so i can help :) x0

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speak2me answered Wednesday March 9 2005, 3:46 am:
it doesn't it equals 4y + y2 (squared)

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MaxwellsSilverHammer answered Tuesday March 8 2005, 11:23 pm:
How about solving it now?

y^2 - 2y = 0
y^2 - 2y + 1 = 1
(y-1)^2 = 1
y-1 = + or - square-root-of(1)

y - 1 = -1
y = -2

OR

y - 1 = 1
y=0

<b>y = {-2, 0}</b>

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