I have this wicked hard homework and its getting me very very very angry. I already have the answer but i dont know how to get it without guessing and checking.. anyone wanna help? the problem is:
The tens digit of a 2-digit number is twice the units digit. The sum of the digits is 12. Find the original number.
S_C answered Friday May 13 2005, 7:30 pm: You have 2 problems, and 2 equations. You can solve it three ways. Graphing, Elimination, or Substitution. We learned this last semester in Algebra 1a, and we've reviewed a few months ago, and now we just reveiwed like last week for our exams.
You need to identify the variables. Y is the 1st digit, X is the second digit.
The two problems
x+y=12
2x=y
The easiest method is substitution because one of the variables is already solved for (y)
x + (2x) = 12 -- simplify
3x=12 -- divide both sides by 3
x=4, now you nead to plug x back into one of the other problems to find Y.
4 + Y = 12 -- subtract 4 from each side
Y=8.
Now just incase plug 4 into the other problem to make sure it works.
2(4)=Y --- simplify
8=Y
So the number is 84.
If you need ANYTHING in math I can so completely help you, I'm making a 96 or 97 out of 100 in that class, so just ask anything if you need it. [ S_C's advice column | Ask S_C A Question ]
Miaka001 answered Friday May 13 2005, 6:57 pm: I don't think there is a way to solve the problem with out guessing and checking.
8+4=12
84
I think most people would use guess and check.
givinadvice2u101 answered Thursday May 12 2005, 8:56 pm: 2x+y=12
divide by 2 on each side
x+y=6
subtract x from each side
y=6-x
that is all i can come up with. i am unsure if this is good enough, but i hope it helps. if not, just guess and check and it doesn't matter if 1 is wrong. [ givinadvice2u101's advice column | Ask givinadvice2u101 A Question ]
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