since the line doesn't go through the ordered pair (0,0)(if the line goes through 0,0 then plug in another small one it doesn't, such as 1,2 etc.), plug 0 into both the y and x places in the original equation (y<2x+1) and solve as if it were y=2x+1. if the left side of the equation is less than the result of the left side, then you shade in the side of the graph under or above the line, whichever side (0,0) is on.
if the left side of the equation is not less than the right side after you solve, then you shade in the side of line on the graph that (0,0) is not on.
did you get that? sorry if it was a little confusing.
leave me a note in my inbox if you need moreh elp! we have already done this in my algebra class.
Hope i helped*
Katie*~ [ brokenheart456's advice column | Ask brokenheart456 A Question ]
kaylalynn answered Friday February 9 2007, 12:44 pm: were doing this is school now ironic! im not too good with it either but i can help much. everthing has to be exaul if you had 1 to 2x you have to do it to "y" . thats as far as i know. maybe ask your math teacher in free time about this. or ask some friends who really get it well. [ kaylalynn's advice column | Ask kaylalynn A Question ]
Ender answered Wednesday February 7 2007, 8:49 pm: Yeah it's easy. Treat it like this, y=2x+1, then make a chart with two columns. The first column with be labeled X, and the second Y. So you pick three numbers, I usually use -5, 0, 5, or -1, 0, 1. Those are your X values. Plug those numbers in for X and write whatever you get in the Y column next to it. Then when you got all three you graph the line. Ok, now the last part. You pick a point on the graph, that IS NOT on the line, then you put the X and Y values in the inequality and if the statement is true, then you shade that side of the line, if it isn't true, then you shade the other side of the line. [ Ender's advice column | Ask Ender A Question ]
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