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Math
Can someone please give me steps and answers to the following, thank you soo much.
1) 5x-2=-32
2)5x-2x+17=33
3)6x=2x+20
4)3x-8=14=8x
5)3(a-5)=2(2a=1)
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To solve problems like these you have to get the variables [like 5x] on one side of the equals sign, and numbers on the other. To do this, you do the same thing to both sides of the equation.
So for number one, you would add two to both sides (that way, you cancel out the -2 on the left side and get 5x alone)
It'll look like this:
5x=-30
Now you have to get x alone (since you're solving for x). Again, you do the same thing to both sides (divide by 5)
5x/5=-30/5
[FYI, it'll be a LOT easier to write it like 5x over 5- like a fraction,instead of sideways, but I can't type it the other way)
So you'll end up with x=-6. Check the answer by substituting -6 for x in the original equation.
5(-6)-2=-32
-30-2=-32
-32=-32
For number two, do the exact same thing as you did for number one. The only thing you'll do differently is first combining like terms. In other words, you can simplify 5x-2x into 3x. Then, get the variable on one side and numbers on the other like before. Number three you'll subtract 2x from both sides- BUT ONLY SUBTRACT INTEGERS! [You should end up with 4x, not 4] Number four I think you wrote wrong, but it'll be the same concept as all the others.
Number five you'll have to distribute the number outside the parentheses. All you're doing is multiplying.
So 3(a-5) will become 3a-15 [because 3 times a is 3a, and 3 times -5 is negative 15]
2(2a-1) you'll do the same thing as you did for the first set of parentheses.
Now your equation will look like this:
3a-15=4a-2
Subtract 3a from both sides, and add two to both sides. Then solve it just like you did number one.
Hope that helped you out. If you need more help, inbox me & I'll be happy to help you, I love math =]
-LM
[15/f]
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