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Math
Okay I need help on this math problem!!
Find the height of a triangle with a base of 4 inches and an area of 6 inches2 (the 2 is sopposed to be small and at the top of the S if ya kno what i mean)
thanx a lot!!!!!!!!!
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The others are correct with the value. The height is 2, but the unit is inches, not inches squared.
area = 1/2 bh
6 in^2 = 1/2 (4 in) h
you multiply 1/2 by 4 in, so the equation will now be:
6 in^2 = 2 in. h
then, you divide both sides by 2 in, so 6 in^2 divided by 2in is equal to 3 in. and 2 in. h is equal to h.
so, 3 in = h.
not, 3 in^2 (3 inches squared).
hope i helped. :)
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You're given the side of a triangle, and asked to find the complementary side. You're given the area of the triangle. Except, the area of the triangle isn't all that meaningful. But consider a square. Just complete the triangle. The area would be 12. One side of the square is 4. What's the length of the other side? 3.
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formula
area of a triangle is = ½ BH
B = base
H = height
so plug in the numbers
area=½BH
6 = ½(4)H
then its a simple problem
½ x 4 = 2
6 = (2)(H)
divide both sides by 2
3 = H
so height is 3 inches². hope that helped.
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