Hey I'm wisemen, I'm 15, I'm single, my yahoo i.d. is wiseguy_2011, and I'm always here to help ask anything and I'll try to answer the best i can so that you will be happy. I'm a very peaceful guy so i don't get mad often, any relationship problems ask me, because most likely I've been in the spotlight once. Thanks!
E-mail: wiseguy_2011@yahoo.com
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5x+4y-z= 1
2x+2y+z= 1
-x-y+z=2
or
3x+y+z=7
x+3y-2z=13
y=2x-1
or
2x+5y+2z=2
x-3y+z=2
3x+2y+5z=0
you have to do it by substitution but im so confused. :( (link)
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you could do it a different way and it comes out the same. 5x+4y-z=1 + -4x-4y-2z=-2 and you get 1x-3z=-1 now 2x+2y+z=1 + -2x-2y+2z=4 and get 3z=4 then add the two equations you have 1x-3z=-1 + 3z=4 and get 1x=-3 then x=-3 thats a part of it now take x and sub. it into one of the two equations u had 1(-3)-3z=-1 then get z alone -3z=2 z=2/3 second part of answer now plug z and x in to an original equation 3-y+2/3=2 makes -y=-1/3 and y=1/3 and the answer is (-3,2/3,1/3).
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