ask MikeDaBoobNinja



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Gender: Male
Member Since: October 23, 2005
Answers: 150
Last Update: December 25, 2006
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A sample of an unknown radioisotope exhibits 8540 decays per second. After 350.0 minutes, the number of decays has decreased to 1250 per second. What is the half life?

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Well, im assuming that the weight or mass starts out as 8540 and goes down to 1250 withen 350 minutes.
8540
/2 = 4270
/2 = 2135
/2 = 1067.5
???
Hmm, this doesn't seem right.
Well, let's see here.
1067.5*2^3=4270
Which would mean that
1250*2^x=8540
This is going to suck to try to solve.
Ok, well the closest answer I got is 2.77235, now divide that by 350
350/2.77235 = 126.246686

So the half life is ABOUT 126.246686 minutes.
That was easily the most I've ever thought about a question on here. Good luck in chem.!

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The Waffler


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